Goal of Problem
Set #1: This assignment is meant to help
you understand:
- the quantities of motion-position,
velocity, acceleration, mass, and force,
- the differences between speed, velocity,
and acceleration,
- what weight is and how it differs
from mass,
- about work and energy,
- about rotational motion,
- and about friction.
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| The Segway Human Transporter or "HT" is
a unique, two-wheeled vehicle that carries a single, standing passenger
at speeds up to 12.5 mph. While its methods of steering, control, and
balance are a bit too complicated for us at this point, much of its basic
physics is already within our reach.
For now, all you need to know about the
Segway HT is that you stand on a platform between two forward-facing
wheels, one to the left of your feet and one to the right. When you
lean forward, the two wheels spin forward and the platform drives forward.
When you lean backward, the two wheels spin backward and the platform
drives backward. And when you turn a steering control, the two wheels
spin at different rates or in different directions and the platform
pivots so that you face a new direction. For more on the Segway HT,
you can watch videos of it in action at http://www.segway.com/video/
or visit the Segway web site at www.segway.com.
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1. You step onto the platform of
the HT and stand there motionless. While you remain still, (A)
what forces (if any) are acting on you and (B) what is the
net force on you?
Answer: (A) You experience your
weight downward and an upward support force from the HT on your
feet. (B) The net force on you is zero.
Why: You are not accelerating,
so the net force you are experiencing must be zero. However, gravity
hasn't vanished so you must be experiencing your downward weight.
To balance that weight and bring the net force on you to zero, the
platform must be exerting an upward support force on you equal in
amount to your weight.
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2. You lean forward and the HT begins
to pick up speed in the forward direction. During this period time,
(A) are you accelerating and, if so, in which direction and
(B) do you have a velocity and, if so, in which direction?
Answer: (A) You are accelerating
forward and (B) your velocity is forward. (Note: for the
first instant of this time period, your velocity is actually zero.)
Why: Since you are heading
forward, your velocity must be forward. That forward velocity is
increasing, so you must be accelerating in the forward direction.
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3. The HT reaches full speed and
you begin to ride it up a smooth, uniform ramp. As you ride straight
ahead up this ramp at full speed,
what are (A) your acceleration, (B) your velocity, (C)
the net force you are experiencing, and (D) the force your
feet are exerting on the platform of the HT?
Answer: (A) Your acceleration is zero,
(B) your velocity is 12.5 mph directly up the ramp, (C)
the net force on you is zero, and (D) your feet are exerting
a downward force equal to your weight on the platform of the HT.
Why: You are coasting at
a constant velocity, which is clearly directed up the ramp and equal
in amount (or magnitude) to the maximum speed of the HT, or 12.5
mph. Since your velocity isn't changing, you are not accelerating
and must be experience zero net force. However, you still have weight,
so the platform must be exerting an upward support force on your
feet with an amount equal to your weight. If the platform pushes
up on your feet, then your feet must push equally hard down on the
platform. Your feet are thus pushing downward on the platform with
a force equal to your weight.
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4. The ramp is 3 meters high and
its paved surface is 50 meters long. As you and the HT climb this
ramp, (A) is one of you (your body
and the HT) doing work on the other? (B) If so,
which one and how much overall work does that one do on the other?
Answer: (A) Yes. (B)
The HT does an amount of work on you equal to the product of 3 meters
times your weight.
Why: The HT is pushing upward
on your feet and they are moving upward (albeit at an angle). During
the travel up the ramp, the HT pushes your feet upward a total of
3 meters and the upward force it exerts on your feet is equal in
amount to your weight. The work done by the HT on your feet is equal
to force times distance in the direction of that force, or your
weight times 3 meters.
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5. You return to level pavement
and then stop briefly to pick up your extraordinarily heavy backpack.
When you start the HT moving forward, you notice that it is now struggling
to pick up speed. (A) What aspect of the backpack is affecting
the HT's ability to pick up speed and (B) why?
Answer: (A) The backpack's
mass is responsible for changing the HT's behavior. (B)
Because the backpack increases the mass of the HT's burden, the
HT must exert more forward force on you and your backpack to make
you accelerate forward at the same rate as before. (Note: an equivalent
answer to (B) is that the HT must do more work on you and
your backpack to bring you up to cruising speed.)
Why: Since the HT is moving
horizontally, its motion is independent of gravity. Support forces
conveyed upward from the ground are responsible for supporting your
backpack's weight, but making your backpack move horizontally is
another matter. With its large mass, your backpack resists acceleration
and the HT must push harder on you and your backpack to make the
two of you accelerate at the normal rate.
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6. You finally reach your friend's
home and slow to a stop. As you and the HT are stopping,
but are not yet stopped, in which direction are (A)
the net force on you, if any, (B) your acceleration, if any,
and (C) your velocity, if any?
Answer: (A) The net force
on you is backward, (B) your acceleration is backward, but
(C) your velocity is forward.
Why: Although your are still
moving forward and thus have a forward velocity, your speed is decreasing.
You are decelerating or, equivalently, accelerating in the direction
opposite your velocity. Your accelerating is backward and the net
force that is causing that backward acceleration must itself be
backward.
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7. As you and the HT come to a stop,
but are not yet stopped, what type(s) of force does the
pavement exert on the HT and in which direction(s)?
Answer: The pavement exerts
an upward support force on the HT and a backward frictional force
on the HT. (Note: unless you skid to a stop, that frictional force
is static friction.)
Why: Support forces act
only are right angles (or perpendicular) to surfaces. Since the
pavement is horizontal, its support forces are only vertical. Therefore,
the only source for horizontal stopping forces is friction. That
friction pushes backward on the wheels of the HT and make it accelerate
backward. Since the wheels merely touch and release, and don't ordinarily
skid, there is no relative movement of the wheel surface across
the pavement. The frictional force is therefore static friction.
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8. To impress your friend, you keep
the HT in one place but pivot the device rapidly around and around.
You begin by (a) pivoting clockwise (as viewed from above)
as fast as possible, then (b) reverse directions, and finish
by (c) pivoting counterclockwise as fast as possible. During
which time or times (a, b, or c) do you (A) have the
largest amount of angular velocity, (B) have the largest amount
of angular acceleration, (C)experience the largest amount of
torque, and (D) have the largest moment of inertia (assume
that you remain rigid throughout this stunt)?
Answer: (A) You have the
largest amount of angular velocity at times (a) and (c).
(B) You have the largest amount of angular acceleration at
time (b). You experience the largest amount of torque at
time (b). And (D) your moment of inertia is constant
throughout this stunt and therefore has the same value at all three
times.
Why: The amount (or magnitude)
of your angular velocity is greatest when you are spinning fastest.
However, the magnitude of your angular acceleration is greatest
when your are changing your rate of rotation as rapidly as possible.
That rapid angular acceleration, or change in angular velocity,
is caused by torque. Thus, at the same time the magnitude of your
angular acceleration is at its maximum, so is the magnitude of the
torque on you. As a rigid object always spinning around the same
axis (vertical), your moment of inertia remains constant.
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